Train icon
A theoretical image on fading tones, made up by equal sized flat filled shapes. With random "dithering".. A theoretical image
Roadsign of curved junction (?) by John Cliff. From OCAL 0.18 release.. Of curved junction
A beautiful logo consisting of intersecting curved lines!. A beautiful consisting
Converted the text to curve, for the case you need it Times New Roman.. Converted the text
Probably the right curve was a circle's involute. "...Its successive turns are parallel curves with constant separation distance..." Not sure how this can be proven, but this seems to fit well with the concept of stroked path -as parallel curves at it's edges-. Mathematical functions for the parametric curve is x=a*(cos(t) t*sin(t)) y=a*(sin(t)-t*cos(t)) More info here: http://en.wikipedia.org/wiki/Involute. Probably the right
View and Look carefully at the white circle Created by Bala Swecha developer and contributer Prabhat. View and look
This shows people falling in front of a profit graph curve.. This shows falling
Parametric functions to plot an ornament. Text is in the clipart off the page borders, NOT converted to paths, so you can select and copy/paste it to inkscape's parametric curve's extension.. Parametric functions to
Ten tones represented by a simple pattern, with the help of gradients. Can be used as a template for a custom hatch filter.. Ten represented by
A theoretical image on fading tones, made up by equal sized flat filled shapes. With random "dithering". At least that was the plan. But couldn't figure out how to construct a halftone with an orderd dithering yet. So this is a bit moving forward. Two sets of ten tones, made by separate gradients. Can be used to draw bases for sources for the image filter primitive for future hatching filter, using ten shades. Does it sound complicated?. A theoretical image
A curvy maze puzzle. Note that the entrance to the maze is in the upper left corner. The exit is in a "delta" in the middle of the bottom of the maze. That means there may be more than one way of getting through the maze, but only one of them is the shortest (albeit quite crooked). Can you find it without looking at my solution?. A note that
Normal/Gaussian distribution curve with boxplot type diagram. Normalgaussian
X=a*(cos(t) t*sin(t)) y=a*(sin(t)-t*cos(t)). Xacosttsintyasinttcost
A wild flower motif, perfect for a border or divider. Drawn by Merlin2525 with Inkscape.. A perfect for
This image was adapted from a picture posted to publicdomainq.net. All of the images on this site are in the public domain i.e. CC0. This site is only in Japanese but can be easily navigated with Google Translate. There are *many* cutesy vector graphics images on this site.. This image was
My remix of this beautiful work. Added a texture filter that gives the image a 3d appearance. Note: Use Inkscape to generate a correctly rendered PNG image. License: Public Domain.. My remix of